Sklansky's modified system

[Magician]

Sklansky has a formula in his modified system to derive a key number:

(Most you can lose/money in pot) * number of limpers+1 * number of players to act

For example: I have T7,000 in the small blind, big blind has T9,000, cutoff +1 has limped in and has T3,800 left, button has limped in and has T4,700 left. Blinds are 100/200 with antes of 25.

Is my key number: (7,000/925 in the pot)*(1 to act)*(2 limpers+1) = 23

Or is my key number: (7,000/925 in the pot)*(3 to act, including the two limpers)*(2 limpers +1) = 69

Is my "number of players to act" the big blind only, i.e. one or is it the big blind plus the two limpers again.

Another question: in the above situation I had a suited ace and decided to move all in. The big blind woke up with AA, called and I was eliminated - was there another way of raising on that hand and getting out if the big blind comes over the top or did I play it fine?

[Scary_Tiger]

You played it fine. You ran into Aces, that's just bad luck.