Dr. Neau's Formula

EasilyFound · #1 10-07-2007, 11:36 AM

How many people here use this formula for calculating points in league play? Find it here. Do you think it is good or bad?

Lottery Larry · #2 10-07-2007, 03:24 PM

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How many people here use this formula for calculating points in league play?

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From that tourney site:

Players are ranked in each tournament using the following formula:

score = (sqrt(((a * b) * (b / c))) / (d + 1.0))

where

a = Tournament Buy-in Count
b = Player Buy-in Expense
c = Player Total Expense
d = Player Finish
The caculator gives these:

19/29= 6.02 points
29/29= 4..01 points
5/29= 20 points
1/29= 60 points

But, it also calculates that $150+5 is 12 points for 29th/29, while $150+15 = 6.95 points?

I'm never a fan of higher buy-in = more points and it seems that the calculator or the equation is doing weird things with the vig, so I wouldn't use it.

EasilyFound · #3 10-07-2007, 05:10 PM

[ QUOTE ]
19/29= 6.02 points
29/29= 4..01 points
5/29= 20 points
1/29= 60 points

But, it also calculates that $150+5 is 12 points for 29th/29, while $150+15 = 6.95 points?

[/ QUOTE ]

I don't understand your numbers or what they represent. Because if I put into the calculator a 29 person tourney, with a buy-in of 155 (150+5), and player total expense of 155, a 29th finish is 2.234 points, not 12 as you seem to say; and a 29th finish is 2.306 if you make the buy-in/player expense $165. So not much difference.

Etaipo · #4 10-07-2007, 07:31 PM

We ganked our formula from either Stars or Party, can't remember which, and it works well for us. If you don't want to adjust points based on $/buyin, just leave that value as a constant of your choosing.

http://flamevault.com/~etaipo/Poker/Season2/tlb.html

pfapfap · #5 10-07-2007, 10:38 PM

I tweaked my own little formula, which seems to work well. If you play every tourney, you'll be in the top ranking, but a solid win or two is more than enough to maked up for some bad times. After using it for nine tournaments, I feel it's accurately ranking my players.

score = (((0.1 * (a - b)) + (10.0 * ((c - d) + 1.0))) + (10.0 * e))

where

a = Player Total Revenue
b = Player Total Expense
c = Tournament Buy-in Count
d = Player Finish
e = Player Knockout Count

EasilyFound · #6 10-08-2007, 09:04 AM

[ QUOTE ]
We ganked our formula from either Stars or Party, can't remember which, and it works well for us. If you don't want to adjust points based on $/buyin, just leave that value as a constant of your choosing.

http://flamevault.com/~etaipo/Poker/Season2/tlb.html

[/ QUOTE ]

I like the formula also, especially after I figured out how to calculate the LOG of a number. I never knew that the calculator on my pc can be switched to a scientific calculator, which has the ability to calcuate LOGs.

Lottery Larry · #7 10-08-2007, 03:28 PM

[ QUOTE ]
[ QUOTE ]
19/29= 6.02 points
29/29= 4..01 points
5/29= 20 points
1/29= 60 points

But, it also calculates that $150+5 is 12 points for 29th/29, while $150+15 = 6.95 points?

[/ QUOTE ]

I don't understand your numbers or what they represent. Because if I put into the calculator a 29 person tourney, with a buy-in of 155 (150+5), and player total expense of 155, a 29th finish is 2.234 points, not 12 as you seem to say; and a 29th finish is 2.306 if you make the buy-in/player expense $165. So not much difference.

[/ QUOTE ]

Maybe I did it wrong- I put buy-in $150 and total expense $5 (I don't understand what "total expense" has to do with anything, regardless... can you explain ?)

Regardless I still say that buy-in has nothing to do with anything other than deep pockets. Now, if we want to weight 200BB tourneys higher that 50BB tourneys, you might get some agreement.

EasilyFound · #8 10-08-2007, 04:23 PM

Yes, I think you did get it wrong. Total expense is buy-in, and would also include add-on and rebuys if you played that kind of tourney.

Now, I agree with you on 200bb tourney vs 50bb tourney. I'm not a math wiz, so I'm not sure how to fit that into the equation.

Another factor would be not only the starting stack size but the speed of the blind escalation.

So many variables. This is why I don't like point systems, but I understand the people who think they are fun.

ericmalone · #9 10-09-2007, 12:25 AM

The most common formula is (n+1-r).

n = number of entrants
r = rank placed

Where out of 10 players, first place gets 10, second gets 9, etc. etc. etc. last place gets 1 point.

This is a bit too loser-friendly for me so I adjusted it to the following:

(n+1-r)+n/r

This makes it easy for the guys to understand, last place always gets 2 points and first place always gets twice the number of entrants, decreasing dis-proportionally as the rank decreases, whereas the better you do, the more you are rewarded.