#31
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Re: Question for David Sklansky or other probability/poker theory expe
Doing computer simulations is probably a better approach to this. I might try out something like this also, perhaps modify my model to see how much needs to change to get a losing game.
Your result so far does indicate that you are still winning. My gut feeling was that the cash taken out would more or less equal the cash put in by villain, so that in the end you would be the only one putting in cash. Perhaps I was wrong. |
#32
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Re: Question for David Sklansky or other probability/poker theory experts
So you are losing at Party and winning other places. Try playing a different site. Just try it. Why not?
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#33
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Re: Question for David Sklansky or other probability/poker theory expe
[ QUOTE ]
Doing computer simulations is probably a better approach to this. I might try out something like this also, perhaps modify my model to see how much needs to change to get a losing game. Your result so far does indicate that you are still winning. My gut feeling was that the cash taken out would more or less equal the cash put in by villain, so that in the end you would be the only one putting in cash. Perhaps I was wrong. [/ QUOTE ] Are you asking who would win if one person had a 50.0001 chance of winning and the other guy had 49.9999 and also pocked a dollar every hand? I would say the guy with the dollar. What does this have to do with this guys losing streak though? |
#34
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Re: Question for David Sklansky or other probability/poker theory expe
Pocketed*
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#35
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Re: Question for David Sklansky or other probability/poker theory expe
[ QUOTE ]
Are you asking who would win if one person had a 50.0001 chance of winning and the other guy had 49.9999 and also pocked a dollar every hand? I would say the guy with the dollar. What does this have to do with this guys losing streak though? [/ QUOTE ] As long as the 50.00001 guy has +EV for every single bet, he wont be losing in the "overall game". Combined -EV bets will not suddenly become +EV, thats why roulette-"strategies" dont work. |
#36
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Re: Question for David Sklansky or other probability/poker theory expe
[ QUOTE ]
[ QUOTE ] Are you asking who would win if one person had a 50.0001 chance of winning and the other guy had 49.9999 and also pocked a dollar every hand? I would say the guy with the dollar. What does this have to do with this guys losing streak though? [/ QUOTE ] As long as the 50.00001 guy has +EV for every single bet, he wont be losing in the "overall game". Combined -EV bets will not suddenly become +EV, thats why roulette-"strategies" dont work. [/ QUOTE ] yeah, but the dollar every hand would compensate I think for the .0001 advantage. Roulette has a much higher advantage than that btw. |
#37
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Re: Question for David Sklansky or other probability/poker theory expe
He doesnt win anything from this dollar, he just takes his own money from the table. How would that help him EV wise?
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#38
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Re: Question for David Sklansky or other probability/poker theory expe
I thought they were saying that he gets a bonus dollar every hand.
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#39
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Re: Question for David Sklansky or other probability/poker theory expe
Nope, the 49.9 player is just "cashing out" max. 1$ per round - if he has any money left on the table. At least thats how i understand it.
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#40
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Re: Question for David Sklansky or other probability/poker theory expe
Oh ok gotcha. I'll go back to sleep then. 8-)
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