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#21
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Oh, and if you look at those numbers again [taking case A] you'll also see why Small Fry's "assine post" saying you can win 1 and lose 4.5 and break even is 100% correct. If you were to loose nine times on the same bet your balance would go down to 82. (100 - (9X2)). To break even you would need to win twice.
[And Small Fry, yes - anyone reading this thread cannot have failed to be 100% impressed by your patience.] |
#22
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LOL
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#23
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Since it appears you're still working on my little "quiz" I'll now add the extra credit question:
You have odds of 1:1. What percent of the time will you win? ps. this is all open book so feel free to check back through previous posts for possible answers. And don't forget to show your work... |
#24
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[ QUOTE ]
Thomas, Just to be clear, in your example: [ QUOTE ] B) The pot is 7, and if you put in your extra bet of 2 the total pot will be nine? [/ QUOTE ] The villian already put 2 in so the pot is 9 my call makes it 11 |
#25
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I do not know why every one is trying to prove me wrong when I say you need 18% or better to call his bet of 2 into a 7 pot. I said that from the beginning. Sorry if YOU are confused.
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#26
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I think what they are trying to point out is that you are saying 1 win to 5.5 losses, where it is actually 1 win to 4.5 losses.
You used Phil's formula to add the 1 correctly so that the denominator represents the total outcomes but then you started using the 5.5 value to represent the losses. It is not 5.5 losses, it is 5.5 total outcomes, represented by 4.5 losses and 1 win. Does this explain it better? |
#27
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i don't know about him, but you guys explained it very well to me. i have really been struggling with this, and still kind of am, but i have a far better understanding of it than before i read this post. thank you to all who tried to help thomas.
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#28
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[ QUOTE ]
4.5:1 odds is equal to an 18% chance of winning. [/ QUOTE ] It has been a while since I've been in school is this a "newer math" |
#29
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no, with their explanation it seems pretty right on.
4.5:1 odds=18% win once in 5.5 trials 3.5:1 odds=22% win once in 4.5 trials. |
#30
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[ QUOTE ]
What is your question anyway? According to these assine post [/ QUOTE ] Had no question was just quoting Phil Gordons formular on pot odds and break even persentages. Not my original thought take it up with Phil |
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