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View Poll Results: Stars of Absolute?
Stars 17 28.33%
Absolute 17 28.33%
I don't know 25 41.67%
other 1 1.67%
Voters: 60. You may not vote on this poll

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  #21  
Old 10-30-2006, 01:38 PM
madnak madnak is offline
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Default Re: Which proof is better? Look again!

[ QUOTE ]
I hardly see how proof 2 is 'more powerful'.

[/ QUOTE ]

Proof Two is more extensible and more intuitive, and therefore has a more powerful impact on the understanding. I read Proof One, I learn that 2 is irrational. I read Proof Two, I learn why 2 is irrational. I learn about other roots, I can even extend some of the understanding to exponential functions, to discrete math, to combinatorics... Proof Two is eye-opening.
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  #22  
Old 10-30-2006, 06:30 PM
bunny bunny is offline
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Default Re: Which proof is better? Look again!

[ QUOTE ]
Proof Two is more extensible and more intuitive, and therefore has a more powerful impact on the understanding. I read Proof One, I learn that 2 is irrational. I read Proof Two, I learn why 2 is irrational. I learn about other roots, I can even extend some of the understanding to exponential functions, to discrete math, to combinatorics... Proof Two is eye-opening.

[/ QUOTE ]
This is why I prefer two as well - it leaves you with some insight into why the result holds, rather than with just a fact about a number. I do think it is harder to understand (although this is partly because it requires more complicated notation which doesnt translate to the internet so well - on paper the notation is not so clumsy imo).

My rather limited survey (around 50 mathematicians) shows a pretty clear (and predictable) distinction between pure mathematicians who prefer the second and applied mathematicians who prefer the first. There have been some exceptions, but not very many.
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  #23  
Old 10-30-2006, 06:41 PM
CityFan CityFan is offline
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Default Re: Which proof is better? Look again!

Count me as another exception then. I like proof one. I can extend it to other roots fairly easily if I like, too.

I like generality, but if you want to be general then prove a general result.
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  #24  
Old 10-30-2006, 06:47 PM
holmansf holmansf is offline
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Default Re: Which proof is better?

I am rather surprised that so many people favor proof 1. I think proof 2 is way better. I think folks are just scared of the "fundamental theorem of arithmetic," even though it is used implicitly in proof 1.
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  #25  
Old 10-30-2006, 07:09 PM
bunny bunny is offline
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Default Re: Which proof is better?

[ QUOTE ]
I am rather surprised that so many people favor proof 1. I think proof 2 is way better. I think folks are just scared of the "fundamental theorem of arithmetic," even though it is used implicitly in proof 1.

[/ QUOTE ]
Well, of course it hinges on what people think makes a good proof which was intentionally left unspecified. I'm more surprised that there arent more "neither" answers, since I had kinda expected this forum to be full of "maths is just a language game - premises to conclusions according to set rules, it doesnt matter how you get there" type people.
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  #26  
Old 10-30-2006, 07:14 PM
bunny bunny is offline
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Default Re: Which proof is better? Look again!

[ QUOTE ]
Count me as another exception then. I like proof one. I can extend it to other roots fairly easily if I like, too.

I like generality, but if you want to be general then prove a general result.

[/ QUOTE ]
You dont think proof two generalises more readily? Just replace "2" with "p for any prime p". I think this is its strength - generalising proof one is not so straightforward (although clearly possible since they ultimately depend on the same thing).
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  #27  
Old 10-31-2006, 12:49 AM
bigpooch bigpooch is offline
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Default Re: Which proof is better?

Technically, Proof One DOES NOT use the fundamental theorem
of arithmetic, but rather uses the result that the square of
an odd integer is odd (or equivalently, if a square of an
integer is even, then the integer is even).
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  #28  
Old 10-31-2006, 12:53 AM
bigpooch bigpooch is offline
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Default Re: Which proof is better? Look again!

Not just that, but from Proof Two, the following proposition
can be readily proven:

For any positive integer, its kth root (where k is an
integer >=2), on the positive real line, is either a
positive integer or irrational (there is no such result that
is rational but not an integer).
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  #29  
Old 10-31-2006, 12:56 AM
bigpooch bigpooch is offline
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Default Re: Which proof is better? Look again!

So, because I studied both pure and applied mathematics,
would you say that I was an applied mathematician or an
exception? [img]/images/graemlins/smile.gif[/img]
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  #30  
Old 10-31-2006, 12:59 AM
FortunaMaximus FortunaMaximus is offline
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Default Re: Which proof is better? Look again!

lol, depends on the rule. [img]/images/graemlins/smirk.gif[/img]
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