![]() |
#21
|
|||
|
|||
![]()
I'm no math wiz, but am I close?
8 9 9 9 10 9 9 9 12 21 22 9 11 13 14 14 14 14 14 14 14 14 14 14 9 9 14 42 41 43 46 45 47 47 48 49 50 51 55 54 44 |
#22
|
|||
|
|||
![]()
[ QUOTE ]
Thank you to everyone who helped and contributed to this post, except for the two bob saget-like attempts at humor by the pirate doofuses [/ QUOTE ] god i hope you get another * for that, if people here have to put up with the crap from your math homework we at least get to make fun of you while we do it. |
#23
|
|||
|
|||
![]()
I have a more elegant solution, and a slightly different answer.
The problem is binomial because it is either effective or not so we can use the binomial probability density function. If you have a Ti83 it will work. binompdf(n,p,k) n = sample space p = probability of success (we determine success as a defective hair dryer) k = exact number of successes we are looking for binompdf(10000,.02,225) = .0058 rJ_ edit*** the reason for our different answers is that mine is exact and you used the normal approximation for a binomial distribution by taking off the .5's |
#24
|
|||
|
|||
![]()
[ QUOTE ]
I want to start this post by apologizing [/ QUOTE ] Denied. |
#25
|
|||
|
|||
![]()
NM
|
![]() |
|
|