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  #11  
Old 06-21-2007, 01:29 PM
binions binions is offline
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Default Re: Odds for Hitting Outs on Turn AND River

[ QUOTE ]
The doubling method works like this;

take your outs (4 in the case of a gutshot) and double it for your chance to make it on the next card (the turn - if your on the flop OR the river if your on the turn) which would give us an 8% chance to make our straight on the next card.

If you are paying to see two cards then double it again 4 doubles to 8 and that doubles to a 16% chance.

This method is a quick and dirty method of calculating your pot odds at the table and it is resonably reliable within a certain range i.e. from about 4 to about 14 outside of this range it begins to lose accuracy.



[/ QUOTE ]

Not really doubling. Just multiplying your outs by 2% for 1 card to come, and 4% for 2 cards to come.

The rule of 4 (for 2 cards to come) actually works pretty well up to 11 outs. After 11 outs, each successive out is worth 3% (until you get way up there in outs). 13 outs twice would be 11*4 + 2*3 = 50%
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  #12  
Old 06-21-2007, 11:28 PM
R Gibert R Gibert is offline
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Default Re: Odds for Hitting Outs on Turn AND River

The 2 basic probability formulas for independent events are as follows:

(1) P(A and B) = P(A)*P(B)

(2) P(A or B) = P(A) + P(B) - P(A and B)

It is the latter that you need to use. You can't just add them together, because the events A and B intersect each other.

Example: If P(A) = 10%, P(B) = 20% are viewed as "lengths," they cannot simply be added together, because the "lengths overlap each other. If the events are independent, then the amount of overlap is P(A)*P(B), which must be subtracted from the sum. Therefore P(A or B) = P(A) + P(B) - P(A)*P(B), which combines the 2 formulas (1) and (2) given above.

As it turns out, if the values for P(A) and P(B) are small, then P(A or B) = P(A) + P(B) can be a very decent approximation. So for the example given above:

P(A) + P(B) = P(A) + P(B) - P(A)*P(B) [approximately]
10% + 20% = 10% + 20% - 2% [approximately]
30% = 28% [approximately]

which may be close enough for practical purposes.


In poker, with 2 cards to come, as an approximation, use:

4*outs, for 8 or fewer outs

3*outs + 8, for 9 or more outs

to compute your chances of hitting your with 2 cards to come.

If you want to be accurate to within 1%, for 11 through 16 outs, use:

3*outs + 9

instead.

These approximations are more than enough for practical purposes and are what I use at the table.
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  #13  
Old 06-23-2007, 06:38 PM
timotheeeee timotheeeee is offline
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Default Re: Odds for Hitting Outs on Turn AND River

I guess I'll have to spend some time rereading this thread. My rough method has always been something like this:

Say I have a flush draw on the flop: 47/9. I treat it as 9 outs twice, so it's 47/18, so roughly 2.6:1 that it comes by the river. If I don't hit on turn, it's 46/9 or 5:1 that it hits on the river. I've never given it much though past this method. I guess I set aside a few hours tonight to decipher all the gibberish I couldn't internalize in my quick read through this thread.
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  #14  
Old 06-24-2007, 09:22 AM
Kurn, son of Mogh Kurn, son of Mogh is offline
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Default Re: Odds for Hitting Outs on Turn AND River

If X=outs on flop/turn and Y=outs on the turn/river and Z=probability of making your hand, then

Z = X/47 + Y/46 - (X/47 * Y-1/46)
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  #15  
Old 06-26-2007, 10:16 AM
BenJammin' BenJammin' is offline
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Default Re: Odds for Hitting Outs on Turn AND River

[ QUOTE ]
i might be wrong, since i'm new to poker as well, but i believe that on the turn,it's the number of outs X 4 = %odds
and on the river it's the #outs X 2...

therefore 10 outs on the turn = 40%
and on the river 10 outs = 20%

i guess that means you're 40% and 20% to win the hand...

i'm sure i'll be corrected if i'm wrong...

[/ QUOTE ]

this is deffinitely correct to some extent.
this method is used by many poker players as the best ESTIMATION of your odds to win the hand.
however i have found that multiplying by 2.5 is a much more accurate estimation with just the river card to come as opposed to multiplying by 2

keep in mind that these are merely estimations and will be off from the true odds by as much as 6 or 7%
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  #16  
Old 06-26-2007, 01:08 PM
d3gener4te d3gener4te is offline
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Default Re: Odds for Hitting Outs on Turn AND River

w0rd
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  #17  
Old 06-26-2007, 01:13 PM
R Gibert R Gibert is offline
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Default Re: Odds for Hitting Outs on Turn AND River

2.5 is--less--acurate that using 2 i.e. 100/46 = 2.1739130435 or about 2.2

I use 2.2 at the table.

Example: 21 outs * 2.2 = 46.2

The true value is 45.652173913. A difference of < 1%

The mechanics of multiplying by 2.2 is no more difficult than multiplying by 2.5 if not even easier e.g. I multiply the number of outs by 2, then add 1 tenth of the result.
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