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  #11  
Old 12-27-2006, 09:33 PM
CheckRaise CheckRaise is offline
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Default Re: Get me into Oxford - Trig problem

[ QUOTE ]
we need that latex support STAT!

[/ QUOTE ]
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  #12  
Old 12-27-2006, 09:39 PM
CheckRaise CheckRaise is offline
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Default Re: Get me into Oxford - Trig problem

[ QUOTE ]
No, sorry I see where the confustion is..(60+T) degrees where T is time in sec. I'm struggling with mathematical notation on the comp.

[/ QUOTE ]

it shouldn't be (60 + T) it should be 60T like we stated earlier unless the 60 is not the angular frequency and if that is the case then I'm not sure how to solve this problem.

This problem is pissing me off, I got an answer for the period but it seems too small to be correct. Anyone else figure it out?
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  #13  
Old 12-27-2006, 09:44 PM
Rolen Rolen is offline
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Default Re: Get me into Oxford - Trig problem

What is your method?
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  #14  
Old 12-27-2006, 09:52 PM
CheckRaise CheckRaise is offline
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Default Re: Get me into Oxford - Trig problem

Ok, I assumed that the w(angular frequency) = 60 rad/sec even though your equation still doesn't make sense.

f(frequency) = w/(2*pi) so plug the numbers in and you get 9.55 Hz

period and frequency are just inverse of one another so T = 1/f and after plugging in the 9.55 you get 0.105 sec.

This seems way to small for something oscillating 80 degrees but I don't know what else to do with the given info.
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  #15  
Old 01-06-2007, 08:23 AM
Goodnews Goodnews is offline
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Default Re: Get me into Oxford - Trig problem

lol wtf

ok, calculate the time T it takes for the pendulum to swing all the way across (X = 80) and multiply by two, giving you the correct frequency (1 cycle/2T seconds), i dont think i need to elaborate from this point.

the above solution is assumed that the pendulum has no external forces changing motion at any point
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  #16  
Old 01-11-2007, 04:07 AM
armPitt armPitt is offline
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Default Re: Get me into Oxford - Trig problem

latex support would be quite handy in some situations
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