![]() |
#1
|
|||
|
|||
![]()
If DS were 40 and he met a 10 year old girl, he'd be four times her age. If they waited 5 years, he'd be 45 and she'd be 15. He'd now be three times her age. If they waited fifteen more years, he's 60 and she's 30. He'd now be twice her age. How long would they have to wait before they were both the same age?
tia |
#2
|
|||
|
|||
![]()
The limit as years waited approaches infinity of the ratio of Sklansky's age to girl's age is one, so in exactly infinity years, they will be the same age.
However, DS only has to wait as many years as it takes for her to lie about her age and run away from home to hit it. |
#3
|
|||
|
|||
![]()
+5 years = 3x
+15 years = 2x +45 years = 1x = same age, ldo |
#4
|
|||
|
|||
![]()
17 years
|
#5
|
|||
|
|||
![]()
10,000 Viagras should do it
|
#6
|
|||
|
|||
![]()
[ QUOTE ]
If DS were 40 and he met a 10 year old girl, he'd be four times her age. If they waited 5 years, he'd be 45 and she'd be 15. He'd now be three times her age. If they waited fifteen more years, he's 60 and she's 30. He'd now be twice her age. How long would they have to wait before they were both the same age? tia [/ QUOTE ] ban |
#7
|
|||
|
|||
![]()
two thumbs up
|
#8
|
|||
|
|||
![]()
This question doesn't compute. He would trade in for a younger girl once the girl hit 16.
|
#9
|
|||
|
|||
![]()
Thread delivers.
|
#10
|
|||
|
|||
![]()
[ QUOTE ]
This question doesn't compute. He would trade in for a younger girl once the girl hit 16. [/ QUOTE ] A+ |
![]() |
|
|