AAxx in omaha

[runhot]

i 'm retarded for some reason i thought the probability of getting dealt two aces in omaha should be 4! * 4/52 * 3/51, but thats like almost ten percent... whats wrong w my thinking here?

[kinghippo423]

C(4,2) * C(50,2) / C(52,4) = 0.027149321

[jay_shark]

It should be 4c2*48c2/52c4 ~ 2.4999% if we're interested in the probability of being dealt AAxx , where the other two cards do not contain aces .

The number of ways of being dealt AAAx is 4c3*48/52c4 ~ 0.000709 or .0709%

The number of ways of being dealt AAAA is 1/52c4 ~ 0.00000369378 or 0.000369378%