How Unlikely?

[___1___]

Since moving to PokerStars I've played...

104,891 hands

So, I guess I'd expect to have 477 of each pair and a 6,198 total pairs...



So how unlikely is it to have only 5852 pairs in 104891 hands?

Thanks,

___1___

[ScottHoward]

a lot less unlikely than never getting pocket 2's

[Dane S]

[img]/images/graemlins/ooo.gif[/img]

[AaronBrown]

You expect 104,891/17 = 6,170 pairs. The standard deviation of that is (6,170*16/17)^0.5 = 76. Your result is 4.17 standard deviations below the expected value, the probability of that is about 1/67,000.

[___1___]

[ QUOTE ]
a lot less unlikely than never getting pocket 2's

[/ QUOTE ]

2s just weren't included in the screenshot. They are included in the total.

___1___

[___1___]

[ QUOTE ]
You expect 104,891/17 = 6,170 pairs. The standard deviation of that is (6,170*16/17)^0.5 = 76. Your result is 4.17 standard deviations below the expected value, the probability of that is about 1/67,000.

[/ QUOTE ]

Thanks a bunch, Aaron...

___1___

[ScottHoward]

[ QUOTE ]
[ QUOTE ]
a lot less unlikely than never getting pocket 2's

[/ QUOTE ]

2s just weren't included in the screenshot. They are included in the total.

___1___

[/ QUOTE ]
so what was the point of the screenshot then?

[___1___]

[ QUOTE ]
so what was the point of the screenshot then?

[/ QUOTE ]

In retrospect, no point. I should have posted the "total" screenshot of the "General" tab in PT.

___1___