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Re: Maths problem
[ QUOTE ]
Ok, so to hell with real work: the nth coeffcient is 4^n(1/2 choose n) = (4^n/2^n) ((1*3*5*...*2n-1)/n!)= =2^n*((2n!)/((2n)*(2n-2)*...*(4)*(2)*n!)=(2^n/2^n)(2n!/(n!n!))= = 2n choose n [/ QUOTE ] There are some sign errors here. Rough idea is right. |
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