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Old 09-03-2007, 01:40 PM
FlawedChip FlawedChip is offline
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Join Date: Nov 2004
Posts: 58
Default Combinatorics / Permutation problem

I have a certain number of items, 26 (A-Z). I would like to find the number of possible combinations by splitting up 100% (1-100) among the 26 items.

Here are a couple of outcomes that would exist for example:

Item Percentage
A: 100
B-Z: 0

Item Percentage
A: 99
B: 1
C-Z: 0

Item Percentage
A: 98
B: 1
C: 1
D-Z: 0

Item Percentage
A: 0
B: 15
C: 30
D-L: 0
M: 20
N: 25
O-Y: 0
Z: 10

Is there a formula to use to count the number of outcomes? I think it might be possible using nCr or nPr?
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