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OT: Deal in WCOOP #2 HU
The two remaining players in the WCOOP #2 stopped play HU to arrange a deal. The two players are rambo and lunoid.
1st is $365,218.75 and 2nd is $205,646.25. However, when a deal is made there needs to be at least $30,000 left to play for. The total in play is $540865. Lee Jones throws out these numbers: Lee Jones [PokerRoom Manager]: Lunoid: $226,116 Lee Jones [PokerRoom Manager]: Rambo: $314,749 Lee Jones [PokerRoom Manager]: $30K in the middle I could really use some help figuring this out. I decided to post this here since we all already know the ICM so the steps are easy to follow. The chip counts are rambo: t9,462,239 lunoid: t1,775,261 To calculate, I went here and plugged numbers in. $365,218.75 / ($365,218.75 + $205,646.25) = 0.63976 Plug 0.63976 into Payout - 1st $205,646.25 / ($365,218.75 + $205,646.25) = 0.36024 Plug 0.36024 into Payout - 2nd Change 3rd to payout 0 Stack Sizes: 9462239 and 1775261 Yield $EV Values: 0.5956 and 0.4044 rambo's $EV is $540865 * 0.5956 = $322139.19 lunoid's $EV is $540865 * 0.4044 = $218725.81 According to the calculator, rambo got stiffed a bit by Lee Jones' proposition. What gives? |
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