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#11
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Not at all. In fact, I had trouble understanding the problem at first, because it's unclear what is meant by a "bisector of a line," given that every point on a line can (arguably) be a bisector.
[/ QUOTE ]I just copied it down as it was in my mathsbook, which is obviously wrong. I'll keep that in mind though, next time my teacher asks
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#12
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[ QUOTE ]
The intercepts are at (0,6) and (12,0). So the sides are 6 and 12, and the hypoteneuse is 6\sqrt{5}. [/ QUOTE ] I agree with this answer. ![]() The black line joins the two points. The red line is the perpendicular line bisecting the black at 4,4. |
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#13
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[ QUOTE ]
[ QUOTE ] [ QUOTE ] Hey guys, I have to do some homework about straight lines. So far I've managed everything without problems, but the I stumpled upon this question: The perpendicular bisector of the straight line joining the points (3,2) and (5,6) meets the x axis at A and the y axis at B. Prove that the distance AB is equal to 6x"square root 5"(I don't know how to do the symbol...) [/ QUOTE ] Kinda hard to prove the distance is 6x"square root 5", when the actual distance is 2x"square root 5". It's a 1 X 2 X SR 5 triangle. Except here the sides are 2 and 4, so the hypotenuse is 2 SR 5. [/ QUOTE ] The intercepts are at (0,6) and (12,0). So the sides are 6 and 12, and the hypoteneuse is 6\sqrt{5}. [/ QUOTE ] And I don't notice till days later that I misspelled hypotenuse. /wrist So much for math nittin'. |
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#14
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[ QUOTE ]
Not at all. In fact, I had trouble understanding the problem at first, because it's unclear what is meant by a "bisector of a line," given that every point on a line can (arguably) be a bisector. [/ QUOTE ]I just copied it down as it was in my mathsbook, which is obviously wrong. I'll keep that in mind though, next time my teacher asks [/ QUOTE ] Not wrong. SenorCardgage posted the correct solution. Your A and B points are wrong. A = (0,6) not (0,4) B = (12,0) not (8,0) The bisector is the point which splits the line into two equal halves. The point is (4,4). You already listed that point in your solution. |
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