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  #1  
Old 01-10-2006, 03:58 PM
graydot graydot is offline
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Default .999~ = 1, Agree?

Several other forums, about 60%+ People think that .999~ infinity is not 1.

Just a stupid poll, vote please


Proof 1:
1/3 = .333333...
2/3 = .666666...
1/3 + 2/3 = .999999... = 1.


Proof 2:

x = 0.9999...
10x = 9.9999...
10x - x = 9.9999... - 0.9999...
9x = 9
x = 1.
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  #2  
Old 01-10-2006, 04:01 PM
graydot graydot is offline
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Default Re: .999~ = 1, Agree?

For those who voted no please state why!
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  #3  
Old 01-10-2006, 04:08 PM
mrkilla mrkilla is offline
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Default Re: .999~ = 1, Agree?

[ QUOTE ]
For those who voted no please state why!

[/ QUOTE ]

a Number can only be that number, no matter what it is.

no mater how many .999's -> you go it will never = the number 1 , ever...
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  #4  
Old 01-10-2006, 04:10 PM
kyro kyro is offline
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Default Re: .999~ = 1, Agree?

[ QUOTE ]
[ QUOTE ]
For those who voted no please state why!

[/ QUOTE ]

a Number can only be that number, no matter what it is.

no mater how many .999's -> you go it will never = the number 1 , ever...

[/ QUOTE ]

Except .999 repeated isn't a specific number. Well, it is. It's 1.
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  #5  
Old 01-10-2006, 04:16 PM
mrkilla mrkilla is offline
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Default Re: .999~ = 1, Agree?

no it can't ever reach the #1 thus why its infinite, its trying to be

.9 is not 1; neither is .999, nor .9999999999. In fact if you stop the
expansion of 9s at any finite point, the fraction you have (like .9999
= 9999/10000) is never equal to 1. But each time you add a 9, the
error is less. In fact, with each 9, the error is ten times smaller.

You can show (using calculus or other methods) that with a large
enough number of 9s in the expansion, you can get arbitrarily close to
1

SO in Math it does = 1 , however in reality it doesn't but its accepted that it is. So is the accepted answer its 1 , then yes, is it really no.
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  #6  
Old 01-10-2006, 04:19 PM
graydot graydot is offline
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Default Re: .999~ = 1, Agree?

[ QUOTE ]
no it can't ever reach the #1 thus why its infinite, its trying to be

.9 is not 1; neither is .999, nor .9999999999. In fact if you stop the
expansion of 9s at any finite point, the fraction you have (like .9999
= 9999/10000) is never equal to 1. But each time you add a 9, the
error is less. In fact, with each 9, the error is ten times smaller.

You can show (using calculus or other methods) that with a large
enough number of 9s in the expansion, you can get arbitrarily close to
1

SO in Math it does = 1 , however in reality it doesn't but its accepted that it is. So is the accepted answer its 1 , then yes, is it really no.

[/ QUOTE ]

I dont think you know what infinity is. You cannot just stop a number, it has no end.

[ QUOTE ]

.9 is not 1; neither is .999, nor .9999999999.


[/ QUOTE ]
.9 is not; neither is .999, nor .99999999.
But .9~ is 1.
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  #7  
Old 10-27-2006, 06:52 AM
CityFan CityFan is offline
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Join Date: Apr 2006
Location: Building a roll (I wish)
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Default Re: .999~ = 1, Agree?

[ QUOTE ]
no it can't ever reach the #1 thus why its infinite, its trying to be

.9 is not 1; neither is .999, nor .9999999999. In fact if you stop the
expansion of 9s at any finite point, the fraction you have (like .9999
= 9999/10000) is never equal to 1. But each time you add a 9, the
error is less. In fact, with each 9, the error is ten times smaller.

You can show (using calculus or other methods) that with a large
enough number of 9s in the expansion, you can get arbitrarily close to
1

SO in Math it does = 1 , however in reality it doesn't but its accepted that it is. So is the accepted answer its 1 , then yes, is it really no.

[/ QUOTE ]

I'm only going to post in this thread once, because I really don't see the point in "arguing" over mathematical results.

I've picked this post to reply to because it is so very wrong.

How can you say "in maths it is one, but in reality it isn't"? 0.999~ is a mathematical construct. The very meaning of that symbol (whatever symbol we choose for it) is "the limit of the given infinite series".

Similarly, it is meaning less to say that the number approcahes one "but never reaches it". What is meant by 0.999~ IS the limit that the series approaches. The series itself is merely a way of expressing the number we wish to express, which is the limit of the series, which is one.

How can you say that 0.999~ has a value "in reality" that is somehow different from the meaning it has in maths? If you have a number in reality that is different from one, then the number you have is not 0.999~, is it? It may be 0.9999999999999, but that is a different number.

Enough. If you wish to use nought point nine recurring to mean something other than it's mathematical meaning, you are merely guilty of abusing the term.
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  #8  
Old 01-10-2006, 06:12 PM
diebitter diebitter is offline
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Default Re: .999~ = 1, Agree?

[ QUOTE ]
For those who voted no please state why!

[/ QUOTE ]

for the same reason 1<>2

Doesn't matter how close they are, they ain't the same.
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  #9  
Old 01-10-2006, 08:49 PM
siccjay siccjay is offline
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Default Re: .999~ = 1, Agree?



The correct answer iz......"Who geevez a sheet!"
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  #10  
Old 01-10-2006, 04:01 PM
Lazy Meatball Lazy Meatball is offline
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Default Re: .999~ = 1, Agree?

try the math forum, and 3/3=1
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