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#1
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Help w/ 2 simple algebra questions please!
If anyone could answer these i would be forever grateful.
Solve for x. x - 2y + 1 = 0 Simplify. 9/y² - 1 / 1+3/y Thank You Im doing 40 problems and these 2 i can't figure. |
#2
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Re: Help w/ 2 simple algebra questions please!
x = 2y-1
9y+27-y^3 |
#3
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Re: Help w/ 2 simple algebra questions please!
[ QUOTE ]
x = 2y-1 9y+27-y^3 [/ QUOTE ] TY but the 2nd one the mulitple choice is A.3 B. y C 1-y D 3-y/y |
#4
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Re: Help w/ 2 simple algebra questions please!
[ QUOTE ]
[ QUOTE ] x = 2y-1 9y+27-y^3 [/ QUOTE ] TY but the 2nd one the mulitple choice is A.3 B. y C 1-y D 3-y/y [/ QUOTE ] D (factor the numerator as a difference of squares, cancel, and then find a common denominator for the binomial left over) If you are stuck and the question is multiple choice, just substitute any number for the variable and see which of the choices gives you the same value as the original question. |
#5
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Re: Help w/ 2 simple algebra questions please!
D 3-y/y
Why wouldnt D simply be 3-1 = 2? Can you show you steps. I am missing something obvious here. |
#6
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Re: Help w/ 2 simple algebra questions please!
[ QUOTE ]
D 3-y/y Why wouldnt D simply be 3-1 = 2? Can you show you steps. I am missing something obvious here. [/ QUOTE ] (3-y)/y not 3-(y/y) (3-y)y = 3/y - y/y which is 3/y - 1 |
#7
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Re: Help w/ 2 simple algebra questions please!
[ QUOTE ]
Simplify. 9/y² - 1 / 1+3/y Thank You [/ QUOTE ] Is it this (9/y² - 1) / ( 1+3/y) or something else? Assume it's the expression above. (9/y² - 1) = (3/y - 1) (3/y + 1) That's from (x²-1) = (x-1)(x+1) The two (3/y + 1)s factor out. Therefore expression two is (3/y -1) |
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