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#1
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D S & young girls..some math help needed
If DS were 40 and he met a 10 year old girl, he'd be four times her age. If they waited 5 years, he'd be 45 and she'd be 15. He'd now be three times her age. If they waited fifteen more years, he's 60 and she's 30. He'd now be twice her age. How long would they have to wait before they were both the same age?
tia |
#2
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Re: D S & young girls..some math help needed
The limit as years waited approaches infinity of the ratio of Sklansky's age to girl's age is one, so in exactly infinity years, they will be the same age.
However, DS only has to wait as many years as it takes for her to lie about her age and run away from home to hit it. |
#3
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Re: D S & young girls..some math help needed
+5 years = 3x
+15 years = 2x +45 years = 1x = same age, ldo |
#4
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Re: D S & young girls..some math help needed
17 years
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#5
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Re: D S & young girls..some math help needed
10,000 Viagras should do it
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#6
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Re: D S & young girls..some math help needed
two thumbs up
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#7
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Re: D S & young girls..some math help needed
This question doesn't compute. He would trade in for a younger girl once the girl hit 16.
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#8
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Re: D S & young girls..some math help needed
Thread delivers.
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#9
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Re: D S & young girls..some math help needed
[ QUOTE ]
This question doesn't compute. He would trade in for a younger girl once the girl hit 16. [/ QUOTE ] A+ |
#10
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Re: D S & young girls..some math help needed
[ QUOTE ]
[ QUOTE ] This question doesn't compute. He would trade in for a younger girl once the girl hit 16. [/ QUOTE ] A+ [/ QUOTE ] |
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