Really need help solving an equation

[LimitGod]

Hi, I'm not good at math. Onto the equation, I'm trying to solve for "A"

0= (A*C)+(1-A)*(B*[C+E])-(1-A)*([1-B]*D)

Any ideas?

[Borodog]

Rewrite as: 0 = C-(1-A)*C+(1-A)*(B*[C+E])-(1-A)*([1-B]*D)

Let A' = 1-A

Solve for A', then A:

A = 1 - C/{C-(B*[C+E])+([1-B]*D)}

If I didn't screw something up.

[JGB]

That rewrite doesn't look right to me...

A*C + (B*[C+E]) - A*(B*[C+E]) - ([1-B]*D) + A*([1-B]*D) = 0
A*C - A*(B*[C+E]) + A*([1-B]*D) = ([1-B]*D) - (B*[C+E])
A*{C - (B*[C+E]) + ([1-B]*D)} = ([1-B]*D) - (B*[C+E])
A = {([1-B]*D) - (B*[C+E])} / {(C) - (B*[C+E]) + ([1-B]*D)}

[Borodog]

JGB,

It appears your solution is identical to mine. It looks like you just put both terms on a common denominator.

[JGB]

Hmm...yes, I guess they are. It's still hard for my head to agree that (B'-D')/(C-D'+B') = 1 - C/(C-D'+B') but it does work out.

[tshort]

Step 1: Copy and paste into mathematica.

Step 2: