#1
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how do I work out % of times I need to win to justify a call in NL
This hand was posted here http://forumserver.twoplustwo.com/showfl...;gonew=1#UNREAD
if you want to see the original. A poster pointed out that you need to win 38% of the time for a call on the turn to be +EV. Can you show me the maths to work this out? Party Poker No-Limit Hold'em, $ BB (6 handed) Hand History Converter Tool from FlopTurnRiver.com (Format: 2+2 Forums) SB ($49.75) BB ($83.69) UTG ($81.95) MP ($68.05) Hero ($50) Button ($54) Preflop: Hero is CO with Q, Q. SB posts a blind of $0.25. UTG calls $0.50, MP calls $0.50, Hero raises to $3, 3 folds, UTG calls $2.50, MP folds. Flop: ($7.25) 5, 7, 4 (2 players) UTG checks, Hero bets $5.5, UTG raises to $11, Hero calls $5.50. Turn: ($29.25) 4 (2 players) UTG bets $40, Hero folds. Final Pot: $69.25 |
#2
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Re: how do I work out % of times I need to win to justify a call in NL
To call : $40
Total pot when you have called : $29.25 + $40 + $40 Neutral EV point : (to call) / (total pot) = 40/(29.25+40+40) = 36.6% Why ? Let's say you win x% of the time. EV = -(to call) + x*(total pot) 0 Ev point : 0 = -(to call) + x*(total pot) Thus x = (to call) / (total pot) |
#3
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Re: how do I work out % of times I need to win to justify a call in NL
thats great. thanks for that. I will try to put it to good use.
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