Party Bad Beat Jackpot Qualifying Hands?

[XChamp]

Rules for BBJ

# The losing hand must contain four of a kind, eights or better to qualify
# The best hand for both the winner and the loser must include both of their hole cards and the hand must go to a showdown

What happens when the board is T[img]/images/graemlins/spade.gif[/img]J[img]/images/graemlins/spade.gif[/img]Q[img]/images/graemlins/spade.gif[/img]Q[img]/images/graemlins/heart.gif[/img]Q[img]/images/graemlins/club.gif[/img]

player 1 has: A[img]/images/graemlins/spade.gif[/img]K[img]/images/graemlins/spade.gif[/img]

player 2 has Q[img]/images/graemlins/diamond.gif[/img]J[img]/images/graemlins/diamond.gif[/img]

Is the BBJ triggered here? Obviously the losing hand is QQQQJ, but is that J the board's or player 2's? Is there any info on Party's site that talks about this situation?

[Reef]

dunno about that situation.

But of course their website isn't updated:
[ QUOTE ]
Bad beats will be paid out on real money Hold'em games (Limits $2/$4, $3/$6, $5/$10, $10/$20 and $15/$30), only available under the Bad Beat Jackpot Tab

[/ QUOTE ]

[Photoc]

Your card is counterfeited in the situation above. There is nothing to determine which card actually plays, since suit and rank are not important.

[DING-DONG YO]

No, both hole cards must play to qualify for BBJ. Only player 2's Q played.

[Pog0]

[ QUOTE ]
No, both hole cards must play to qualify for BBJ. Only player 2's Q played.

[/ QUOTE ]

Why doesn't his J play? I'd imagine it does.

edit: whenever a site shows the winning 5-card combination, it seems to include a players hole card kicker rather than board kicker if it's the same rank.

[bottomset]

im pretty sure you choose which J to play in your QQQQJ hand

[XChamp]

so is the winning hand QQQQ+J[img]/images/graemlins/spade.gif[/img] (board card) or QQQQ+J[img]/images/graemlins/diamond.gif[/img] (player's card)?

It's arbitrary, so which one does Party choose?

[bobbyi]

[ QUOTE ]
so is the winning hand QQQQ+J[img]/images/graemlins/spade.gif[/img] (board card) or QQQQ+J[img]/images/graemlins/diamond.gif[/img] (player's card)?

It's arbitrary, so which one does Party choose?

[/ QUOTE ]
At every casino I have ever played at with a jackpot except for one, it was the player's card that plays in this scenario and it is a jackpot. The one that did it the other way had tons of unhappy people about it because it was so non-standard, so they changed it. I don't know about Party though.

[XChamp]

Good. We now have a precedent.