AA vs KK

Riverbnd07 · #1 08-22-2007, 06:44 PM

Just a simple question. To get the odds of 2 players, one getting dealt AA the other KK you just mutiply 1/220 * 1/220 or is this not correct?

jay_shark · #2 08-22-2007, 07:24 PM

If it's heads up it's 1/221*1/221 .

The odds against receiving pocket aces is 220:1 so the probability of getting dealt aces is 1/221 . The same is true for kings .

DarkMagus · #3 08-22-2007, 07:24 PM

That would be the odds of one specific player getting AA and the other getting KK. If you don't care who gets which, then you have to multiply that by two.

Also, it's still not exactly correct since you have to remove the AA from the deck when dealing to the player who gets KK.

The correct way would be:

2 * (4/52 * 3/51) * (4/50 * 3/49)

which equals 0.000044325

or about once in every 22560 hands

BruceZ · #4 08-22-2007, 07:31 PM

[ QUOTE ]
If it's heads up it's 1/221*1/221 .

[/ QUOTE ]

Shark, you know better than this...

jay_shark · #5 08-22-2007, 07:52 PM

Grrrrrr

It's 6/1326*6/1225 = 0.00002216 . If you want player one to have aces and player two to have kings . Or , multiply this by 2 if you don't care about the order .