Mathematics Question

Degenerasian · #1 09-13-2007, 02:29 AM

Hey guys,

My provincial lottery runs this NFL pool where you have to pick all the winners of that week's games. Each ticket costs $5. Let's say I (for example) want to lock 7 games out of the 16 this week, and for the rest of the 12 games, cover both winning possibilities. Does anyone know the mathematical formula to calculate how much this will cost me? It would be greatly appreciated.

housenuts · #2 09-13-2007, 03:30 AM

it'll cost you however much money you spend cuz i guarantee you your 7 locks won't win

Degenerasian · #3 09-13-2007, 03:40 AM

[ QUOTE ]
it'll cost you however much money you spend cuz i guarantee you your 7 locks won't win

[/ QUOTE ]

I never said I had 7 locks this week. GG reading skills.

drenx · #4 09-13-2007, 09:33 AM

There'll be 2 to the power of 9 possible combinations - 512, so it would cost you $2560

4Tay · #5 09-13-2007, 10:49 AM

I know the football pool you're talking about, everyone in my office plays it. Last year, I was 13/15 one week. The more money you put down, the more games you can exempt. I don't think you can exempt more than 4 games (OP mentions 7 games). To exempt 4 games, you have to pay $80 per ticket. This also means you only have to get 12 of 16 picks correct to win the pool.