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  #1  
Old 02-10-2007, 10:07 PM
Braaak Braaak is offline
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Join Date: Feb 2007
Posts: 5
Default What are the odds of this?

PokerStars Game #8369189563: Tournament #42663150, $5.00+$0.50 Hold'em No Limit - Level IV (50/100) - 2007/02/10 - 09:41:38 (ET) Table '42663150 1' 9-max Seat #2 is the button Seat 2: Jax946 (2465 in chips) Seat 3: Princehorn (2125 in chips) Seat 4: Écureuilmort (1425 in chips) Seat 5: Braaak (1795 in chips) Seat 6: touchdownKC (1745 in chips) Seat 7: JacksorK5 (2455 in chips) Seat 8: blynky (4890 in chips) Seat 9: Zimaks (1005 in chips)
Princehorn: posts small blind 50
Écureuilmort: posts big blind 100
*** HOLE CARDS ***
Dealt to Braaak [Ad Kd]
Braaak: raises 200 to 300
touchdownKC: folds
JacksorK5: folds
blynky: folds
Zimaks: raises 705 to 1005 and is all-in
Jax946: calls 1005
Princehorn: raises 1120 to 2125 and is all-in
Écureuilmort: folds
Braaak: calls 1495 and is all-in
Jax946: calls 1120
*** FLOP *** [Td 8h Tc]
*** TURN *** [Td 8h Tc] [Qd]
Écureuilmort said, "LOL"
*** RIVER *** [Td 8h Tc Qd] [Th]
*** SHOW DOWN ***
Princehorn: shows [Ac Ks] (three of a kind, Tens)
Jax946: shows [Kc Ah] (three of a kind, Tens) Princehorn collected 330 from side pot-2
Jax946 collected 330 from side pot-2
Braaak: shows [Ad Kd] (three of a kind, Tens)
Jax946 said, "what a setup"
blynky said, "wooow"
Princehorn collected 790 from side pot-1 Braaak collected 790 from side pot-1
Jax946 collected 790 from side pot-1
Zimaks: shows [Kh As] (three of a kind, Tens) Princehorn collected 1030 from main pot Braaak collected 1030 from main pot Zimaks collected 1030 from main pot
Jax946 collected 1030 from main pot
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  #2  
Old 02-10-2007, 11:05 PM
Elandriel Elandriel is offline
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Join Date: Sep 2004
Posts: 776
Default Re: What are the odds of this?

100%
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  #3  
Old 02-11-2007, 01:03 PM
AaronBrown AaronBrown is offline
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Join Date: May 2005
Location: New York
Posts: 2,260
Default Re: What are the odds of this?

There are 16 AK's out of 52*51/2 = 1,326 hands. Once one player gets AK, there are 9 left out of 50*49/2 = 1,225 hands. Once two players get AK, there are 4 left out of 48*47/2 = 1,128. The last player has only one AK to get out of 46*45/2 = 1,035 hands.

Multiply them all together and you get 576 chances in 3,792,792,276,000 or 2 in 13,169,417,625. With 9 players there are 9*8*7*6/(4*3*2*1) = 126 different ways to choose the four players. That makes it about 1 time in 52 million.
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