Two Plus Two Newer Archives  

Go Back   Two Plus Two Newer Archives > General Gambling > Probability
FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
  #1  
Old 05-31-2006, 08:37 PM
wall_st wall_st is offline
Senior Member
 
Join Date: Jul 2004
Location: overpriced coinflips
Posts: 1,003
Default Risk of Ruin playing blackjack surrender

I am playing blackjack surrender on bet365.com with 200 bets. Can anyone tell me what my risk of ruin is and how do I calculate it ?
Reply With Quote
  #2  
Old 05-31-2006, 09:49 PM
BruceZ BruceZ is offline
Senior Member
 
Join Date: Sep 2002
Posts: 4,078
Default Re: Risk of Ruin playing blackjack surrender

[ QUOTE ]
I am playing blackjack surrender on bet365.com with 200 bets. Can anyone tell me what my risk of ruin is and how do I calculate it ?

[/ QUOTE ]

This is a negative expectation game, and the risk of ruin for a negative expectation game is always 100%.
Reply With Quote
  #3  
Old 06-10-2006, 08:21 AM
JimDrang JimDrang is offline
Senior Member
 
Join Date: Dec 2005
Posts: 190
Default Re: Risk of Ruin playing blackjack surrender

Is there a site/calc where you can get specific %s for risk of ruin depending on how many bets you make at a certain $ amount with a certain BR?
Reply With Quote
  #4  
Old 06-10-2006, 01:56 PM
AaronBrown AaronBrown is offline
Senior Member
 
Join Date: May 2005
Location: New York
Posts: 2,260
Default Re: Risk of Ruin playing blackjack surrender

Figuring out your exact risk of ruin depends on the details of the game. In most cases of real games, the best approach is just to simulate a lot of outcomes.

You can get a pretty good approximation using the expected return and standard deviation of each bet. For example, suppose you pay $1 to flip a fair coin and get $X if you win. Your expected value per flip is $X/2 - 1. Your standard deviation per flip is $X/2.

After N flips, your expected profit is N*(X/2 - 1) and your standard deviation is (N^0.5)*X/2. You can use the Excel NORMDIST function to get the approximate probability of having lost B or more dollars:

=NORMDIST(-B,N*(X/2 - 1),(N^0.5)*X/2,TRUE)

However, if you started with B dollars, your chance of going broke on or before the Nth flip is greater than this. This is the chance that a guy with unlimited credit would be down B or more dollars after N flips. In some cases, he would have lost B dollars, but later had a winning streak to get positive.

If your expected value is zero, that is, if the game is fair, your chance of being broke is exactly twice the formula above (this is due to the "reflection" principle). If your expected value is not zero, there's no simple formula for the answer, but there are ways to compute it.
Reply With Quote
Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 03:55 AM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.