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#1
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I am flipping a fair coin and counting the number of heads vs. the number of tails after each flip.
Can I prove that an infinite sequence of coin flips can always be reduced to the following: r = f(r1) + f0 + f(!r1) + f0 + f(r1) + f0 + ... where r1 is the result of the first flip f(r1) is a sequence of some number of flips (n) where the excess of heads/tails is in the same direction as r1 - that is to say if r1 is a head, f(r1) would be the sequence of flips where each count is an excess of heads, or zero. f(!r1) is a sequence of some number of flips (n) where the excess of heads/tails is in the opposite direction as r1. f0 is a sequence of exactly 1 flip where # heads = # tails. Does it comes down to showing that n is always a finite number?? Is this possible? TIA. |
#2
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Infinite number of coin flips, mean that any excess either way is infinite to.
See Hilbert's Hotel for explanation! |
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