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Old 11-05-2007, 07:26 AM
Buzz Buzz is offline
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Join Date: Sep 2002
Location: L.A.
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Default Re: probability homework question

Hi Bruce - Thanks for your response. I had already resolved to stay out of your hair from now on.[img]/images/graemlins/crazy.gif[/img][ QUOTE ]
and the number of ways to get the other 2 cards <font color="red">4*4</font>.

[/ QUOTE ]If you have chosen the specific lower and higher rank, that's true. Otherwise there are, for threes, for example, 2*4=<font color="blue">8</font> lower cards, excluding aces, and 9*4=<font color="blue">36</font> higher cards, also excluding aces.

And then we have to add in the aces. Where Z can be anything but a three or an ace in A333Z, there are <font color="blue">44</font> cards that can be the Z, not just <font color="red">4</font>.

Buzz
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