Re: Maths problem
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Ok, so to hell with real work: the nth coeffcient is
4^n(1/2 choose n) = (4^n/2^n) ((1*3*5*...*2n-1)/n!)=
=2^n*((2n!)/((2n)*(2n-2)*...*(4)*(2)*n!)=(2^n/2^n)(2n!/(n!n!))=
= 2n choose n
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There are some sign errors here.
Rough idea is right.
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