Re: wonky O8 starting hand statistics - do I have the numbers right?
[ QUOTE ]
Chance of being dealt AA2x where x is not an ace
c(4,2) *c(4,1) *c(47,1)/c(52,4)=0.004167
[/ QUOTE ]Hi Frank - I just looked at the first one (quoted above). I'll look at the others later and report if I see something amiss. Don't have time right now.
For the first one (quoted above)
AA22 6*6=36 ways to be dealt this.
AA2X 6*4*44 = 1056 ways to be dealt this (where X is neither an ace nor a deuce).
All in all there are 36+1056 = 1092 ways to be dealt AA2x where x is not an ace.
Then 1092/C(52,4) = 1092/270725 = 0.00403.
There are probably some other ways to set it up. But you can't simply use 4*47. I'm not very good at explaining why something doesn't work but think of it this way: three of the cards in the 47 are also deuces. You probably can find a way to do the calculation without making a two line chart with a separate line for two deuces - but that's how I did it this time. And that works. And that gives you a different answer.
Hope that helps.
Buzz
Make the first line C(4,2)*C(4,2) instead of 6*6, then calculate to get 36 if you like.
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