Re: Blackjack q - continuous shufflers - can they be beaten?
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I still not convinced a 2 deck penetration will provide a good enough count into 6 decks ...
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You would need a 12+ running (using a single level count) to make your bet. The frequency of that situation will be so low, the min/max ratio required for your top bet will (in all probability) push you over table limits. At the very least, the spread you need will draw a lot of unwanted attention. I think the zero memory game needs to offer you more than -.004 to beat a 2 deck penetration into a 6 deck game (and my simulations agree with me [or the other way around]) [img]/images/graemlins/wink.gif[/img]
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