[Sweet]

[ QUOTE ]
Sweet, what you're missing is that when you have a ratio of:

N/D

Decreasing D increases the value of the fraction, but so does increasing N. Since "n" in this value would be the expected "reward" (i.e. how much money you make overall), then EV is still very important according to this model and can still trump decreased variance much of the time.

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Well, I didn't actually miss that. I didn't claim that the player with the higher Sharpe ratio cannot be the best player. I did observe that there are ways for your EV to decrease while your Sharpe index increases, which, from my position, means that claiming the player with the higher Sharpe ratio is "the better player" is digustingly false. I gave a $10,000,000,000 example that I thought made this pretty clear. No?