Re: one more pf. qq for azk
Just to be unambigious, let's do a little math.
The correct decision here, or any time in poker, is the decision with the highest EV. Folding has an EV of zero by definition. So if calling is +EV, you have to call.
Assuming we are a 2:3 dog and are getting 260:530, and that the fishy limper will fold, the EV of calling is:
EV = (chance to win * $ won) - (chance to lose * $ lost)
= (0.40 * 530) - (0.60 * 260)
= 212 - 156
= +56
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