[runout_mick]

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blinds at 300/600, player A limps for 600, player B raises to 3000 and player C reraises all in for 4,200.

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Now that we've established that A can raise, I do have a follow-up question. What is the minimum raise amount for player A?

My guess is that the underraise really functions (as someone else said) as a "call plus some extra chips", in which case I would expect that the minimum raise would be calculated off of B's raise (as if C had "just called").

But this has always confused me and I can't find a clear explanation of it in Robert's (would appreciate pointer if it is in there)

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Player A must use the total chips that are over his original bet as a basis for a minimum raise. So that is 4200-600=3600. Player A must make it a minimum of 7800 to go.

Think of it this way. It is the same as if Player B had raised to 4200 and that just happened to be exactly what Player C had left to go all-in. It's also the same as if Player B had called Player A and then Player C pushed in for 4200.

Also think of it this way. When the action is to you after you have bet, your original bet is already part of the pot. So now to call a raise back to you, you need to put in amount X, which is the amount of the raise to you. You now need to at least double that X to make a minimum raise.

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Actually, I believe player B set the raise increment at 2400 (since player C's all-in is treated as a call, it doesn't increase the size of the increment) and the minimum re-raise player A can make is to 6600 (current bet of 4200 + current raise increment of 2400).

Please correct me if I'm wrong. This is just my understanding of it.