Re: math Problem in Tournament poker for advanced Players ( Sklansky)
Hm, the actual setup is:
You are offered a 120$:100$ coin-flip today.
You are offered a 200$:100$ coin-flip tomorrow.
But you only own 100$.
So, the thing you are missing here is that, if we loose the first coin-flip, we will pass out on the second one.
So, 50% of the time we will end up with nothing (-100$), because we loose our first bet. 25% of the time we win both coin-flips for winnings of +320$, and 25$ of the time we win the first, but not the second flip, resulting in +20$.
So, taking the first bet, we have an expectation:
0.5*(-100$)+0.25*320$+0.25*20$ = +35$
If we skip the first bet, and only take the second one, we have an expectation of +50$.
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