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Prob. of getting 2 pr. in 5 card draw poker?
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11-21-2007, 06:40 PM
bigpooch
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Join Date: Sep 2003
Location: Hong Kong
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Re: Prob. of getting 2 pr. in 5 card draw poker?
C(13,2)xC(4,2)xC(4,2)x(52-2x4)= 123552; divide by C(52,5)
to get 123552/2598960 or about 0.047539016.
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