Re: Help with SD calculations for hand distributions
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How do you calculate the standard deviation for, say, the number of times you will be dealt a given set of hands over a given number of deals?
Example: Standard deviation for # of times dealt AA,KK,QQ,AKs over 16k hands? Or your example, but you get the idea.
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SD = sqrt(npq)
where
n is the number of hands
p is the probability of getting one of the hands in question on any given hand
q = 1 - p
This is the standard deviation of the binomial distribution over which the number of these hands is distributed.
In your example, there are 22 hands in question, so p = 22/C(52,2) = 22/1326. SD = sqrt(16000 * 22/1326 * 1304/1326) =~ 16.2
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