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combinatorial argument
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08-13-2007, 01:01 AM
jay_shark
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Join Date: Sep 2006
Posts: 2,277
Re: combinatorial argument
Show that 1^4+2^4+3^4+...+n^4 = 24*(n+1)c5 +36*(n+1)c4 + 8*(n+1)c3 + 6*(n+1)c3 + (n+1)c2 for n>=4
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