Re: Chance of nuts beating second nuts with same ranks, suits?
Odds of being dealt a non-pair: 16/17
Odds of them being unsuited: 3/4
Odds of opponent drawing the one exact hand to fit the requirements: 2/50 * 1/49 = 1/1225
Odds of a result other than a tie: 25,334 in 1,712,304
16/17 * 3/4 * 1/1225 * 25,334/1,712,304 = 1 in 117,295.
Odds of me calculating the odds of it being nuts vs second nuts: 0
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