Re: probability of higher ace-x
Here is a simple explanation .
If you're at a 10-handed table and you hold A-x , then the approximate probability that someone has pocket aces is :
1-[(1225-3)/1225]^9 ~ 0.021826135
The probability player i doesn't have pocket aces is (1225-3)/1225 . We may approximate the solution by assuming independence . So the probability neither of the 9 players holds pocket aces is [(1225-3)/1225]^9 . Now the last step is to take the complement which is 1 - [(1225-3)/1225]^9 .
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