Re: Olympiad problem with cubes
Using the "lingo" of the post by TC that was in white:
54 = 8^3 - 6 x 63 - 2 x 26 - 4 x 7
(Okay, so it's not THAT easy to see this geometrically!)
Also, looking at everything (mod 7),
53 is congruent to 39 and 20 = 27-7, so 39 = 20+20-1 is
possible
(if a cube can be dissected into x1 subcubes or x2 subcubes
it obviously can also be dissected into x1+x2-1 subcubes)
EDIT: much easier is 53 = 27+26
52 is congruent to 38 = 64-26
51 = 6^3 - 5 x 26 - 5 x 7 (geometrically ok)
50 is congruent to 1
49 = 6^3 - 4 x 26 - 9 x 7 (geometrically ok)
48 is congruent to 27
47 is not possible
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