Re: Basic starting hand odds
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Hey, when I'm bored at work I try to figure out odds for various situations in different variants of poker I play. So I've been trying to figure out the odds of being dealt a Pineapple hand where two, but not three, of the cards share the same suit. Typically I can reason it out to choose notation but I'm having a brain fart right now and can't seem to do it. Can anyone write out the expression for determining this? For those who don't know, Pineapple is a game with three-card starting hands.
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4*C(13,2)*39 / C(52,3)
=~ 55.1% or 1.2-to-1 favorite
OR
52/52 * 12/51 * 39/50 * 3
=~ 55.1% or 1.2-to-1 favorite
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