Thread: 10/20 -QQ - 30 to 1 , folding middle set
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Old 10-26-2007, 07:55 PM
Heisenb3rg Heisenb3rg is offline
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Default Re: 10/20 -QQ - 30 to 1 , folding middle set
Wolfram his math is wrong.
Quote:

"if the chances of winning against ANY of the callers is 1/3 we should have called"

This is not true... its
p[beating all 3] = P[beating A] * P[beating B] * P[beating C]

they are all indepdent variables..
If B is > 1/3, the term on the leftside can still be < 1/30.
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