[yellowjack]

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i'm trying not to be results oriented, but if the chance we are winning against any of the callers is 1/3, we should have called.

e.g. P[beating all 3] = P[beating one]^3 = (1/3)^3 = 1/27, and we are getting 26.5 to 1.

just thought i'd put that out there.

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thats so wrong heh.
If we are beating one caler 100% of the time and another 0% of the time, we still lose the pot.

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it was a figure i threw out there
in addition, i just took chance of beating one person as 1/3, i didn't use the 0% chance anywhere at all