Re: odds question
I am not a math expert but I believe this is correct.
If you assume that your five opponents play any King.
There are 47 unseen cards, consisting of 2 Kings and 45 non-Kings. The total number of ways to have 10 hole cards for the 5 opponents is c(47,10). The total number of ways to not have a King in these hole cards is c(45,10).
The probability that someone does not have a King is c(45,10)/c(47,10). 1 - c(45,10)/c(47,10) =~ 0.384 is the probability that someone does have a King.
For four: 1 - c(45,8)/c(47,8) = 1 - 215553195/314457495 =~ 0.315
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