[Sevenfold]

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whats wrong with this?->

(12/52) + (12/51) + (12/50) = K,Q,or J hitting ~70.5%

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In laymans terms, what are the odds of me flipping at least one heads in two tosses?
50% + 50%=100%

You have to work backwards. The odds of not hitting a head (50%) times N flips.

Here it would be 50%(.5) x 50%(.5) = 25% (.25)

So you would hit a head 75% of the time in two flips.