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Probability of 2 PP's at 9 handed table?
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10-11-2007, 07:55 PM
EasilyFound
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Join Date: Mar 2005
Posts: 924
Re: Probability of 2 PP\'s at 9 handed table?
[ QUOTE ]
C(9,2) * (3/51)^2 * (48/51)^7 = 0.0815
[/ QUOTE ]
I guess I should know the answer to this, but I don't.
What does the "," in "9,2" stand for?
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