Thread: Solving problems in Reverse
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Old 10-10-2007, 11:36 AM
SheetWise SheetWise is offline
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Join Date: Jul 2005
Location: Phoenix
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Default Solving problems in Reverse
If I want to calculate the probability of having at least one diamond in a draw of two cards -- I will subtract from 1 the probability of having no diamonds in two cards,

1 - (39/52 * 38/51) = 1 - .5588 = .4412

What if I wanted to work the problem forward instead of backwards -- what would be the easiest way?
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