Re: Probability of 2 PP\'s at 9 handed table?
Do you mean if you know you look down and see you have a PP, what are the chances that "at least one" other player has one also? I suspect this is what you're looking for.
Or do you mean, 'if you dealt nine hands out, what are the chances that exactly two players have pairs and the other seven do not'?
Each player has about a 5.88 percent chance of being dealt a pair individually, but it's easier to answer if you clarify that.
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