[Lottery Larry]

[ QUOTE ]
It doesn't matter what he knows, it matters what is probable. And it's more probable that the deck was more ace-rich without those disgards dealt back in.

[/ QUOTE ]

Is it significant enough to matter?
3 Aces, 48 unknown cards= 1/16 chance that any card is an Ace.

87.5% of the cards are in the stub before the shuffle. So, it's an average of 2 5/8 Aces in the stub, vs. 3/8 of an Ace in the folded cards. Both are 1/16 chance.... so it doesn't change?

eh.. I'm too tired to think through this properly.

However, if the Ace loses by diluting the Ace-richness, he also gains by extra straight cards, extra 7's....

Never mind. I give up