Re: What are the odds of pocket aces beating pocket aces?
n/50c2=n/1225 is the probability that if you hold aces , then one other player will hold aces, against n other opponents .
50c2 is the number of ways of selecting two objects from a collection of 50 objects .You may also find this button on most calculators so just look for n(c,r) or nCr .
For your second question , did you mean four flush on the flop ?
If that's the case, given that two players hold aces , it should be
2*12c3/48c3=2.54%
To radrad:
I already showed how one would get 2.17% .
2*[12c4*36 + 12c5]/48c5=2.173913%
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